Jun. 16th, 2005

Is ax^2 + bxy + cy^2 really the equation for two lines through the origin? I didn't think thhe absence of x, y, and K terms would be enough to make the conic section degenrate, but thatt's what I think I've derived. I haven't tested it.

What I think I've derived, is that two non-vertical lines through the origin with slopes m and n are specified by x^2 - (M+N)*xy + mn*y^2.

Well, let's see. Is the quadratic b^2 >= than the 4ac?
((M + N)y)^2 >=? to 4MN*y^2
(M + N)^2 >=? 4MN
M^2 + N^2 >=? 2MN
Yes.

Set m=n=K and we get
x^2 - 2K*xy + K^2*y^2 = 0
(x - Ky)^2 = 0
x = Ky

So it looks good.

sigs

Jun. 16th, 2005 12:58 pm
I think I'll start rotating sigs on Usenet. I want to include
"I was able to get a sense of [Putin's] soul, a man deeply committed to his country and the best interests of his country," -- George W. Bush
"The creatures outside looked from pig to man, and from man to pig, and from pig to man again; but already it was impossible to say which was which." -- George Orwell
but I don't want to stop using
Any time you get members of a government preaching out -against
government-, it's a sure bet they're looking to replace it with whatever
ELSE they own. -- Skyler Bode
which I pulled from one of [livejournal.com profile] tactisle's posts.

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